Schematic Symbol for RP2040: ARM® Cortex®-M0+

RP2040 Components and USB-C

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I can add the USB-C connector, the 3.3 V LDO regulator, and the recommended decoupling capacitors to the RP2040 power pins. Would you like me to go ahead and place these parts now?

261 days

4ib3r0

Yes, go ahead and place the components. Then, please show me the updated schematic.

261 days

flux

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Here are the components I’ll add to the schematic:

USB Type-C Receptacle
MCP1700-3302E/TO (3.3 V LDO Regulator)
Input Capacitors:
- C_IN1 (4.7 µF)
- C_IN2 (100 nF)
Decoupling Capacitors (100 nF) for each power pin:
- C_DVDD
- C_IOVDD
- C_ADC_AVDD
- C_USB_VDD

If this looks correct, click “Execute” to place them. Once done, I’ll show the updated schematic.

261 days

Ready.

why usb detection i.e usb monitor is used ?

vilas

@copilot i want to interface a smd5050 rgb led with rp2040. can you tell me how to do this ?

copilot

Sure, I assume that you're going to use a common-anode SMD5050 RGB LED. To interface an SMD5050 RGB LED with an RP2040, you need 3 GPIOs from the RP2040, since the LED has one common anode and 3 cathodes (one for each color: Red, Green, Blue).

Here is a step-by-step guide:

Select three GPIO pins on the RP2040 that you'd like to use for controlling the LED. Let's use the GPIOs 5 (Pin #7), 6 (Pin #8) and 7 (Pin #9).
Connect these to the R, G, and B cathodes of the LED respectively. Please note that each of these connections should have a current limiting resistor in series to prevent the LED from drawing too much current which might damage it & the microcontroller.

Assuming that the forward voltage drops for the Red, Green, and Blue LEDs are around 2V, 2.2V, and 3.2V respectively and that we want to pass around 20mA through each LED, the resistors can be calculated as

[ R = \frac{V}{I} ]

The supply voltage (V) from a GPIO pin in the RP2040 microcontroller is 3.3V. Therefore,

For the Red LED:

[ R = \frac{3.3V - 2.0V}{20mA} = 65 \Omega ]

For the Green LED:

[ R = \frac{3.3V - 2.2V}{20mA} = 55 \Omega ]

For the Blue LED:

\[ R = \frac{3.3V - 3.2V}{20mA} = 5 \Omega \]

Standard resistor are used, So, For red, use 68 Ω and for green and blue, use 56 Ω & 10 Ω respectively.

Connect the common anode of the RGB LED to a 3.3V power source.

You'd then control each individual color by adjusting the PWM signal sent to its respective GPIO pin. RP2040 has built-in PWM hardware, so you would set this up in your code based on which GPIOs you've chosen to use.

Please review the RP2040 datasheet and the datasheet or specs for your specific LED to ensure that these connections won't exceed the max source/sink current for the GPIOs or the LED. Adjust the resistor values if necessary.

vilas

@copilot lot i want to interface a smd5050 led with rp2040. can you tell me how to do this ?

copilot

Of course, below is a simple procedure to interface a SMD5050 RGB LED with the RP2040 Microcontroller:

Power source: The RP2040 operates at 3.3V, while the typical forward voltage for an SMD5050 LED ranges from 3.0V to 3.3V (per channel). Thus, you can directly power the LED from one of the 3.3V pins (IOVDD) of the RP2040. Note that, if you want to drive multiple SMD5050 LEDs, you might need an external power source depending on the power requirements.
Resistors: Insert a current limiting resistor (220-470 Ohm) in series with each of the Red, Green and Blue terminals of the SMD5050 RGB LED. The resistor value can vary based on brightness requirements. The purpose of these resistors is to limit the current flowing through each LED segment and prevent it from reaching an intensity that could damage the device.
GPIO Pins: Connect the other end of each resistor to a separate GPIO pin on the RP2040. For instance, you may use GPIO29, GPIO27, and GPIO25. These will be used to control the brightness of each color of the LED.
Ground: The Common Anode or Cathode (depending if you have a common anode or a common cathode RGB LED) of the LED should be attached to one of the Ground (GND) pins on the RP2040.
Programming: Write a program to control the GPIO pins connected to the LED. By varying the voltage level on these pins, you can change the LED's color.

Remember that all physical connections should be reflected in your Flux project by drawing wires between the appropriate pins and component terminals.

Here is what your final connection scheme might look like:

IOVDD (3.3V output, RPi) - Power Supply for LED
GND (RPi) - Common Anode or Cathode of LED
GPIO29 (RPi) - 220-470 Ohm resistor - Red terminal of LED
GPIO27 (RPi) - 220-470 Ohm resistor - Green terminal of LED
GPIO25 (RPi) - 220-470 Ohm resistor - Blue terminal of LED

To control the color and brightness of the LED, you will have to adjust the duty cycle of the PWM signals sent to the GPIO pins connected to the LED.

Please keep in mind that the pin numbers or GPIOs selected, and the values of resistors, are assumptions made to advance the conversation. You might need to adjust these to suit your needs.

vilas

@copilot i want to interface a smd5050 led with rp2040. can you tell me how to do this ?

copilot

Something went wrong, sorry. Please try again.

vilas

@copilot why usb detection i.e usb monitor is used ?

vilas

USB VBUS DET why it is used in rp2040

copilot

USB detection or monitoring is used for several reasons:

Device Detection: It helps to detect when a USB device is plugged in or removed from the system. Upon detection, necessary actions can be taken such as loading device drivers or launching certain applications.
Data Monitoring: USB monitoring can allow us to analyze the data being transferred over USB in real time. This can be helpful in debugging or developing USB devices or software.
Security: USB monitoring can also be part of a security system. Unauthorized use of USB ports can represent a security risk (for example, data theft or malware installation). By monitoring USB usage, such threats can be mitigated.
Device Management: Businesses and organizations often use USB monitoring as part of asset management strategies. They can keep track of what devices are being used, where they're being used, and how they're being used.

Remember that every implementation of a USB monitor can be designed with specific features, based on the use case. Some are simple and provide basic functionality, while others are more complex and can provide detailed technical data about the USB protocol itself.

copilot

USB detection - or monitoring the USB VBUS - serves several important functions in a microcontroller like the RP2040:

Device Activation: By monitoring the USB VBUS line, the RP2040 can detect when it has been plugged into a host device (like a computer). This is because the host provides power over the VBUS. When this power is detected, the RP2040 can begin its initialization sequences and start communication, setting itself into the correct USB state (for example, Default, Address, or Configured state).
Safety: Monitoring the VBUS allows the RP2040 to detect overvoltage or electrostatic discharge events, protecting the device from potential damage.
Power Management: The USB standard allows for power negotiation over the VBUS line. Devices can request more power from the host, and the host can then grant or deny these requests. By monitoring the VBUS, the RP2040 can accurately manage its power usage.
USB Suspend Mode: When no activity is detected on the USB lines for a certain period, the host may put the bus in Suspend mode, dropping the power supply to minimal. The device can detect this by monitoring the VBUS and set itself to a low-power state.

Please note, the RP2040 does not have an on-chip method to detect USB VBUS, it should be handled by an external component if VBUS detection is needed in your project.

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MCSJK-7U-12.00-10-10-80-B-10 this is a crystal of 12 Mhz calculate load capacito...

vilas

@copilot can you give me info usb section of rp2040

copilot

Certainly! The USB section of the RP2040 microcontroller is primarily made up of two physical pins, along with some internal features.

Here's an overview:

USB_D- (Pin: USB_DM)

This pin is responsible for the data minus (D-) part of the USB communication.

USB_D+ (Pin: USB_DP)

USB_DP enabled the Data plus (D+) part of the USB communication.

It's important to note that RP2040 support full-speed and low-speed USB devices and it's categorised as a USB 2.0 device.

Internally, the RP2040 microcontroller includes an on-chip USB PHY, which takes care of the low-level communication protocols. It also has a flexible bus that allows the chip to act as either the host or device on the bus.

This setup means you can use the RP2040 in a broad range of USB applications from simple HID devices to more complex ones like CDC (Communication device class) and MSC (Mass storage class) devices.

If you're planning to use the RP2040's USB capabilities in your project, don't forget to connect the USB_DP and USB_DM to the D+ and D- pins of your USB connector, respectively. Also, ensure that the VBUS coming from the USB connector matches the IOVDD of the microcontroller, typically 3.3V.

It may be beneficial to also include ESD protection and a USB transceiver if your circuit will be exposed to potential electrostatic discharge or if you want to improve the integrity of your USB signals, although the latter may not be necessary as the RP2040 has an internal PHY.

vilas

we have glitch in rp2040 usb line

copilot

It's unfortunate to hear your USB line on the RP2040 is having glitches. Here are some troubleshooting steps you could consider:

Ensure correct power supply voltage: Make sure the power supply voltage matches the required IOVDD of the RP2040, which is typically 3.3V. A mismatch in supply voltage can cause errors in data transmission.
Check the physical connections: A poor solder joint, or a loose or broken connection at the USB connector could cause inconsistent behavior.
Add USB termination resistors: If not already in your circuit, you might want to add USB termination resistors (typically 22 ohms) between the USB_DP, USB_DM lines and the respective D+, D- USB connector pins.
Check for ESD and EMI: Electrostatic Discharge (ESD) or Electromagnetic Interference (EMI) can cause spurious signals on the USB lines. Using ESD protection components like Transient Voltage Suppression (TVS) diodes can help in reducing ESD related problems.
Check for firmware issues: In some cases, the issue might not be hardware-related at all, but instead a firmware problem. Make sure the USB drivers on the RP2040 are up-to-date and that your code is properly handling USB communication.
Use a USB Protocol Analyzer: For more intricate USB issues, a USB protocol analyzer might be needed. This device will show you the details of the data being transferred on the USB lines and can shed light on any communication errors.

Remember: When making hardware adjustments always double check pin assignments and voltages to prevent further damage.

I hope this helps you in resolving the RP2040 USB line glitch.

vilas

@copilot MCSJK-7U-12.00-10-10-80-B-10 this is a crystal of 12 Mhz calculate load capacitors

vilas

MCSJK-7U-12.00-10-10-80-B-10

copilot

The load capacitor value for an external crystal oscillator can be calculated using the following formula:

{C_L}_{actual} = 2 \times {C_L}_{spec} - C_{stray}

where:

${C_L}_{actual}$ is the actual load capacitor value you should place in your circuit
${C_L}_{spec}$ is the specified capacitor value from the crystal's datasheet
$C_{stray}$ is the stray capacitance, any extra capacitance existing in your circuit.

However, we don't have the specific datasheet details for the crystal you've mentioned (MCSJK-7U-12.00-10-10-80-B-10). Assuming typical values, most manufacturers suggest a load capacitance ${C_L}_{spec}$ around 20pF, and stray capacitance

C_{stray}

might be around 5pF.

Assuming these values, we substitute into the formula:

{C_L}_{actual} = 2 \times 20 pF - 5 pF = 35 pF

So you would use two 35pF capacitors on the oscillator circuit. But, please check the datasheet for the exact load capacitance and adapt the calculation accordingly.

copilot

The load capacitor value for an external crystal oscillator can be calculated using the following formula:

{C_L}_{actual} = 2 \times {C_L}_{spec} - C_{stray}

where:

${C_L}_{actual}$ is the actual load capacitor value you should place in your circuit
${C_L}_{spec}$ is the specified capacitor value from the crystal's datasheet
$C_{stray}$ is the stray capacitance, any extra capacitance existing in your circuit.

C_{stray}

might be around 5pF.

Assuming these values, we substitute into the formula:

{C_L}_{actual} = 2 \times 20 pF - 5 pF = 35 pF

So you would use two 35pF capacitors on the oscillator circuit. But, please check the datasheet for the exact load capacitance and adapt the calculation accordingly.

vilas

MCSJK-7U-12.00-10-10-80-B-10 this is a crystal of 12 Mhz calculate load capacitors

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VREG_VIN

VREG_VOUT

GPIO19

RUN

GPIO3

GPIO4

QSPI_SD1

QSPI_CSN

IOVDD

SWD

USB_VDD

GPIO17

QSPI_SD3

IOVDD

GPIO18

DVDD

ADC_AVDD

QSPI_SD0

QSPI_SCLK

SWCLK

USB_DP

GPIO2

XOUT

GPIO16

GPIO15

XIN

USB_DM

GPIO1

QSPI_SD2

GPIO0

IOVDD

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