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is my connection correct for this project ?
2y
From the provided project description, it looks like you are building a simple power supply circuit with an LM7805 voltage regulator and you have two capacitors (C1 and C2) for smoothing and stability.
Looking at the nets you've created:
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Net c94a670d00b53ae2a5aa9a6fcdf63520 includes the VBUS of the USB plug, the input (VI) and the output (VO) of the LM7805, and the P2 pin of both capacitors C1 and C2.
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Net 83221888ae2718719dc794addb9b35e2 connects GND of the USB plug, GND of the LM7805, and P1 of both capacitors C1 and C2.
Let's look at what these connections mean:
- You have connected the positive lead of both capacitors to both the input and output of the LM7805 voltage regulator.
- The ground of the USB (GND) is connected to the ground of the LM7805 (GND) as well as to the negative lead (P1) of both capacitors.
There's an issue here: input and output of the LM7805 should not be connected together. Instead, every capacitor should be connected separately to the input and output of the LM7805. Please revise your connections as per the following:
- Connect USB:(VBUS) -> C1:(P1) -> LM7805:(VI) -> C1:(P2); this will connect the LM7805 input to the USB power through capacitor C1
- Connect LM7805:(VO) -> C2:(P1) -> C2:(P2); this will connect the LM7805 output to capacitor C2
- Connect all GND pins together: USB:(GND) -> C1:(P1) -> C2:(P1) -> LM7805:(GND); this will ground all components.
Assuming all other connections are correct and the capacitors C1 and C2 are positioned correctly (C1 on the input side of LM7805 and C2 on the output side), then this should correct the schematic. The capacitors will stabilize the input and output of the LM7805, creating a smoother voltage transformation.
In terms of capacitor values, it's common to use a larger value electrolytic capacitor (e.g., 10uF, C1) at the input and a smaller value ceramic capacitor (e.g., 100nF, C2) at the output. However, that's the usual setup; your actual values may depend on the specific power requirements of your circuit. Please consult the LM7805 datasheet for specifics.
2y
is it correct ?
2y
Based on your question, it seems you might be asking for a verification after making changes. Unfortunately, I can only provide advice based on the information you've previously given. I'm afraid I didn't receive any updated schematic or project information to review.
But here's how your circuit should be connected:
- Input Side:
- Connect the VBUS of the USB connector to the P1 pin of Capacitor C1.
- Connect the P2 (or the other lead) of Capacitor C1 to the VI (Input) of the LM7805.
- Output Side:
- Connect the VO (Output) of the LM7805 to P1 pin of Capacitor C2.
- Connect the P2 (or the other lead) of Capacitor C2 to Ground.
- Grounding:
- Connect all grounds together. This includes:
- GND of the USB connector
- P1 of Capacitor C1 (if not yet grounded from the input side)
- P1 of Capacitor C2 (if not yet grounded from the output side)
- GND of the LM7805.
Usually, the VBUS of the USB plugs into the input side of the voltage regulator (LM7805 in this case) through a capacitor (C1), and the output of the voltage regulator connects to the second capacitor (C2). Both capacitors then have their negative terminals tied to the ground along with the GND pin of the LM7805 and the GND of the USB connectors.
If you've wired things up this way, everything should be all set. However, if there's any problem, you could give me a description of the changes you've made so that I can verify them. Or if you haven't made the changes yet, know that based on the previous project, the above recommendations are correct.
2y
4
C2
Capacitance
100nf F
USB
LM7805
End of Life
C1
Capacitance
10uf F
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