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R1 is only connected to the source pin (S) of Q1(a MOSFET) and Pin 1 of LED1(K). We can assume it's the load resistor for the LED. However, pin 1 of R1 is not connected to any other component or to power, thus the circuit is currently incomplete.Q1, the MOSFET, is correctly connected between the resistor R1 and the relay coil K1: S pin of Q1 is connected to P2 of R1 and D is connected to A2 of K1.K1, the relay, has COM connected to PIN2 - that is what the user intends, but without any load (for example, an appliance) at the output side, it's not possible to visualize the context of the relay operation. However, NC and NO are connected to PIN3 and PIN1 respectively, which doesn't seem to serve any purpose.J1 is a connector and may provide external connections to other circuits or loads. However, we lack sufficient information to understand how it should work.LED1) is present but it's connected directly to the power supply V1 (5V) on the anode side, and to P1 of R1 on the cathode side. This could potentially cause an excessive current to flow through the LED, destroying it, as LEDs should usually have a series resistor to limit current. The forward Voltage of the LED is 1.7V, so with a 5V supply the excess voltage needs to be dropped across a resistor we can use ohm's law to calculate: $R = \frac{V}{I}$, where we assume I (current) is around 20mA, then R turns to be 165 Ohms. We have a 1k resistor in the circuit, but it's not connected properly.V1 is supplying 5V, which is connected to A1 of K1 and A of LED1. The relay is operating properly with this supply.PowerNet1 a positive 5V power rail, you can add a label to it specifying the voltage. Here's how to do it on Flux:PowerNet1 on the schematic.Edit button.Label field, enter 5V.Save button.Reviews
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Ideal Coral Antigravity Battle Room
Controls
Properties
Availability & Pricing
| Distributor | Qty 1 | |
|---|---|---|
| Digi-Key | $0.10–$0.43 | |
| LCSC | $1.21–$1.22 | |
| Mouser | $0.38 | |
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rusty61
copilot
rusty61
copilot