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how do I export the schematics for altium ?
ambroggio

ambroggio

@copilot how do I export the schematics for altium ?
1y

copilot

Flux doesn't currently support the direct export of schematics to Altium. However, there is a workaround to this problem. Here are the steps you can take to achieve this:
  1. Export as Eagle: Start by exporting your design from Flux as an Eagle project. In Flux, select File -> Download -> Eagle Project.
  2. Open the Eagle project and export as Altium: If you have Eagle, you can then open this and use its built-in export to Altium functionality via File -> Export -> Altium.
Be aware that there could be some minor issues due to differences in the way Flux, Eagle, and Altium interpret certain components or values. Once the project is brought into Altium, carefully review especially the schematic and PCB layout for any discrepancies and correct them as necessary.
Always remember to validate the exported files in Altium to ensure that no connections or components were lost or altered during the conversion process.
As a note, for future projects where you know you will be using Altium, you might consider designing directly in Altium to save this conversion step and avoid any possible conversion-related issues.
Keep in mind that the conversion process from one software format to another could cause some inconsistencies or errors. Thus, it's essential to perform a thorough inspection of the converted data in Altium.
1y
Someone is typing...
I don't understand why LED3-Detector is independent to SW1 since the positive ca...
ambroggio

ambroggio

how can I unwire everything?
2y
ambroggio

ambroggio

@copilot I don't understand why LED3-Detector is independent to SW1 since the positive cathode of V1-Transformer 5V is connected to SW1 and if it is closed no charge will be faced by R1
2y

copilot

You are correct in noticing that when switch SW1 is closed, there will be a connection between the anode of the transformer V1-Transformer 5V and resistor R1. However, this setup does not make LED3-Detector dependent on switch SW1.
In your current configuration, LED3-Detector and R3 form a simple series circuit with the power sources V1-Battery and V1-Transformer 5V. Therefore, LED3-Detector is not directly controlled by SW1.
Since it gets powered irrespective of whether SW1 is open or closed, the behavior of LED3-Detector is independent of SW1.
Here's the key:
  • Net 5cdda32fce86755d9df39daa855bcac4 connects all anodes of the two voltage sources (V1-Battery and V1-Transformer 5V) to the resistors R3 and K1 (pin A1) and the cathode of LED3-Detector.
  • Net 9546189b6431d5ab6d21e16f23ff8f31 connects the anode of LED3-Detector with resistors R3 and R2.
The switch (SW1) affects the relay coil (K1 pins A1 and A2), which further drives the relay's contact between Common (COM) and Normally Open (NO) or Normally Closed (NC). This configuration determines whether LED1-Board or LED2-Battery gets powered. However, the circuit of LED3-Detector with R3 and the power sources remains unaffected by the status of SW1.
2y
ambroggio

ambroggio

I am still confused since the Cathode of LED3-Detector connects the resistors R3 and R2 not the anode. So the cathode of LED3 is linked to the cathode of V1 when SW1 is closed
2y

copilot

I apologize for the confusion earlier, let's clarify this:
  • The cathode of LED3-Detector is indeed connected to resistors R3 and R2 through Net 9546189b6431d5ab6d21e16f23ff8f31.
However, the key factor to consider is how current flows:
  • Current generally flows from a higher electrical potential (positive side or Anode) to the lower electrical potential (negative side or Cathode).
  • LED3-Detector is being powered from the positive terminals (anodes) of both V1-Battery and V1-Transformer 5V through resistor R3, regardless of the position of switch SW1.
To analyze the effect of closing SW1, let's examine what happens:
  • The current will flow from V1-Transformer 5V's anode to its cathode, passing through R1, SW1, and then join the main ground net 5cdda32fce86755d9df39daa855bcac4.
  • This same ground net is also connecting the cathode of LED3-Detector and one terminal of R3.
  • So, the current in the LED3-Detector's circuit is now divided between the R2 and the path through SW1.
However, this doesn't stop the current from flowing through LED3-Detector, as the other end of R3 is still connected to the positive terminals (anodes) of V1-Battery and V1-Transformer 5V, and current can still flow from these sources through R3, LED3-Detector, and finally into the common ground net.
I hope that clears up the confusion! Please feel free to ask if you have further questions.
2y
ambroggio

ambroggio

Still I'm confused, I understand that the anode of LED3-Detector is common to negative terminals of V1-Battery and V1 Transformer (anodes). But if SW1 is open, to the best of my knowledge, then there is no positive terminal connected to the cathode of LED3-Detector.
2y

copilot

I sincerely apologize for the confusion. You're correct, when SW1 is open, there is no direct path from the cathode of LED3-Detector to the positive terminal of the power sources (V1-Battery and V1-Transformer 5V). This means that LED3-Detector should not be on unless SW1 is closed.
Let's revise the circuit flow:
  • When SW1 is closed, the anodes of V1-Battery and V1-Transformer 5V (through R3) are connected to the cathode of LED3-Detector. This allows current to flow from the power sources through R3 and LED3-Detector to the common ground (cathodes of V1-Battery and V1-Transformer 5V via SW1 and R1).
  • This completes the circuit and LED3-Detector should light up.
  • When SW1 is open, the circuit between the power sources and LED3-Detector is broken. The cathode of LED3-Detector is no longer connected to the anodes of V1-Battery and V1-Transformer 5V. The LED3-Detector should not light up in this scenario as there is no complete path for current to flow.
That makes LED3-Detector's state dependent on SW1. I apologize for the confusion in the earlier responses and appreciate your patience.
2y
ambroggio

ambroggio

And what will be the status of the other LEDs when SW1 is open and closed?
2y

copilot

Based on the schematic description provided, here's the expected status of LED1-Board and LED2-Battery for both positions of SW1:
SW1 closed (activated):
  • LED1-Board: This LED will not light up when SW1 is closed. The reason being that, the relay (K1) would be energizing as the Switch SW1 provides the path for the current from V1-Transformer 5V through R1 to relay K1 (across pins A1-A2). When the relay is energized, the connection between the COM (common) and NO (normally open) of K1 is established. However, no current flows from COM to NO, so LED1-Board stays off.
  • LED2-Battery: This LED will light up when SW1 is closed. As the relay energizes when SW1 is closed, the connection between NO and COM of relay K1 breaks, and NC (normally closed) and COM of K1 connect. This forms a path for the current to flow from V1-Battery through LED2-Battery to the common ground.
SW1 open (deactivated):
  • LED1-Board: This LED will light up when SW1 is open. The relay (K1) de-energizes when the switch SW1 is open, breaking the path from V1-Transformer 5V to K1. This reestablishes the connection between COM and NO of Relay K1, allowing current to flow from V1-Battery, through LED1-Board to the common ground.
  • LED2-Battery: This LED will not light up when SW1 is open. The relay K1, being de-energized, separates NC and COM of K1 breaking the current path from V1-Battery through LED2-Battery.
I hope this response clarifies the status of the LEDs relative to the switch position. If you have further questions, please, let me know.
2y

copilot

I apologize for the oversight. You're correct, NO is connected to the cathode of V1-Transformer 5V after the switch SW1 through the net a9bb770cf66b6762a024fb2f5b343535.
Let's revise the status of the LEDs again:
SW1 closed (activated):
  • LED1-Board: The LED1-Board should light up. The reason is when SW1 is closed it closes a path from the anode of V1-Transformer 5V, through SW1 and K1 (A1-A2) to its cathode. When K1 is energized, the COM and NO contacts close, completing a circuit from the anode of the V1-Battery, through LED1-Board to the cathode of V1-Transformer 5V return path.
  • LED2-Battery: The LED2-Battery will be OFF. When K1 is energized the NC and COM contacts open, breaking the circuit for LED2-Battery.
SW1 open (deactivated):
  • LED1-Board: The LED1-Board will be OFF. When SW1 is open, it breaks the path from the anode of V1-Transformer 5V, through SW1 and K1 (A1-A2) to its cathode. The relay K1 will de-energize, breaking the COM and NO contacts and the current flow through LED1-Board stops.
  • LED2-Battery: The LED2-Battery will light up. When K1 is de-energized due to SW1 being open, the NC and COM contacts close, completing a circuit from the anode of V1-Battery, through LED2-Battery, and to the cathode of V1-Battery, thus lighting up LED2.
I hope this clears up the situation better. Let me know if you need any further assistance.
2y
ambroggio

ambroggio

Sorry but indeed there is a connection beween NO and the cathode of V1-Transformer 5V after the switch.
2y
ambroggio

ambroggio

How can I delete all the nets and wirings?
2y

copilot

In Flux.ai, you can delete all the nets and wiring using the following steps:
  • Open the Flux.ai browser-based tool and load your desired project.
  • To delete the wires, navigate to your circuit schematic, click on the wire you want to delete. Once it's selected, press "Delete" or "Backspace" on your keyboard. Repeat this step until all wires are removed.
  • To delete the nets, navigate to the "Nets" section on the right panel of your screen. In this list, you can select a net, and click on the "Delete" or "Trash bin" icon to remove it. Repeat this step until all nets are deleted.
Doing this will remove all the nets and wires from your project. But please note, without any wiring or nets, your components in the schematic will be disconnected, and the circuit will not function.
As always, don't forget to save your project frequently to avoid losing your progress. After deleting, if you find you've made a mistake, you can use the "Undo" button or the "Ctrl/Cmd+Z" shortcut to revert the last action.
2y
Someone is typing...
6
R3
Resistance
10000 Ω
V1-Transformer 5V
C1
Capacitance
1000uF
LED3-Detector
D2
V1-Battery
LED1-Board
D1
K1
R2
Resistance
10000 Ω
R1
Resistance
10000 Ω
LED2-Battery
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RelayLED

RelayLED
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Last updated by ambroggio
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ambroggio

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