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To control a 24V, 40mA appliance using the CPC1017N solid state relay, we'll need to create a simple schematic. The CPC1017N is a photo MOSFET relay that can handle the required voltage and current. Here's how you can set it up:
Resistor for current limiting (optional for signal, if needed)
Control Signal (from a microcontroller or other switching device, typically 3.3V or 5V)
Schematic Setup:
Input Side of the Relay (Control Signal):
Connect the control signal (from a microcontroller or other switching device) to the input side of the CPC1017N relay. Typically, this is pin 1 (anode) and pin 2 (cathode).
If your control signal source is lower than required, a current-limiting resistor may be used according to the required input current for the relay input side. However, this typically might not be needed directly connecting to a microcontroller output, but double-check your datasheet.
Output Side of the Relay (Load Control):
Connect the 24V positive terminal to one side of the appliance (e.g., one terminal of a motor).
Connect the other terminal of the appliance to pin 3 (normally open contact) of the CPC1017N.
Connect pin 4 (common contact) of the CPC1017N back to the 24V supply ground.
Connections:
Control Signal:
Connect control signal to CPC1017N:1 (anode).
Connect CPC1017N:2 (cathode) to ground or return path of the control signal.
Load Path:
Connect 24V supply positive to the appliance positive terminal.
Connect appliance negative terminal to CPC1017N:3 (normally open).
Connect CPC1017N:4 (common) to the return path of the 24V power supply.
This setup will allow you to control the appliance using the control signal you provide to the relay input. Let me know if you need more details or any adjustments!
When controlling the CPC1017N solid state relay with a 3.3V microcontroller, it's important to consider the input characteristics of the relay. The CPC1017N has an LED input that typically requires a certain forward current to operate properly. Let's go through the details:
Input LED Specifications
Forward Voltage ($V_f$): Usually around 1.2V (check the datasheet for exact value).
Forward Current ($I_f$): Typically around 5mA to 10mA.
Calculating the Resistor
You need a resistor to limit the current to a safe level for the input LED. Using Ohm's Law and the formula for a current-limiting resistor:
R=IfVcontrol−Vf
With a 3.3V microcontroller and assuming:
$V_f = 1.2V$
$I_f = 5mA$
R=0.005A3.3V−1.2V=420Ω
A 420Ω resistor is a non-standard value, so you can use a 430Ω resistor, which is a standard value.
Conclusion
Use a 430Ω resistor on the control signal side between the microcontroller pin and the relay's input anode pin.
This will ensure that the input current is within the safe operating range while preventing any excess current from damaging the relay's LED input. Let me know if you need further details or assistance with your design!
3mo
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Passive Components
Resistor Power Rating
Beta
Checks that the power traveling across a given resistor is under its rating with 50% headroom.