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  • Generic Inductor
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  • RMCF0805JT47K0
    47 kOhms ±5% 0.125W, 1/8W Chip Resistor 0805 (2012 Metric) Automotive AEC-Q200 Thick Film #forLedBlink
  • 875105359001
    10uF Capacitor Aluminum Polymer 20% 16V SMD 5x5.3mm #forLedBlink #commonpartslibrary #capacitor #aluminumpolymer #radialcan
  • CTL1206FYW1T
    Yellow 595nm LED Indication - Discrete 1.7V 1206 (3216 Metric) #forLedBlink
U1
Manufacturer Part Number
MT3608
R1
Resistance
39k Ω
D1
Manufacturer Part Number
1N5817WS
C2
Capacitance
10u F
L1
Inductance
4.7u H
C1
Capacitance
10u F
R2
Resistance
2k Ω

Low Current Boost Converter based on MT3608

Low Current Boost Converter based on MT3608
Description

Created
February 3rd 2022
Last updated by jharwinbarrozo
2 months ago
1 Contributor(s)
jharwinbarrozo

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can you suggest equivalent replacement for MT3608?
@copilot can you suggest equivalent replacement for MT3608?
3mo
I don't have direct access to databases for component specifications, but I can suggest some equivalent boost converter ICs based on the MT3608, which is a 1.2MHz step-up converter designed for small, low power applications. Some potential alternatives might include:

  • TPS61032 by Texas Instruments: A step-up DC-DC converter that can handle similar voltage ranges and has a high switching frequency.
  • MIC2605 by Microchip Technology: Offers similar features with low-profile package options.
  • LT1302 by Analog Devices: Another boost converter with similar applications, although its switching frequency is lower, which might affect your inductor size if space is a constraint.
  • NCP1406 by ON Semiconductor: A high-efficiency step-up DC-DC converter suitable for 12V applications.
These parts may differ in terms of package size, voltage, and current capabilities, so be sure to check the specific datasheets and verify that the component meets the required specifications of your design, such as input/output voltage and current requirements. If you have more specific constraints or requirements, please let me know!
3mo
what does this circuit do?
@copilot what does this circuit do?
3mo
This circuit is a boost converter, designed to increase (or "boost") a lower input voltage to a higher output voltage. It's using the MT3608, which is a step-up converter IC.
Here are some key points about this circuit and its components:

  • Input and Output: The circuit takes a (likely lower) input voltage through the IN connector and provides a boosted output voltage through the OUT connector.
  • MT3608 IC (U1U1): This IC is responsible for the voltage boost. It uses a switch-mode power supply design to perform the boost conversion efficiently.
  • Inductor L1 (CPY160808T-4R7M-NP): Connected to the switching pin of the MT3608, the inductor stores energy when the switch is on and releases energy to the load when the switch is off. This is a crucial component in the boost operation.
  • Diode D1 (1N5817WS): Used to ensure current flows in the correct direction during the energy release phase of the boost operation.
  • Capacitors C1 and C2 (C0603X5R106M250NT): These are used to filter the input and output voltages, smoothing the supply and output to reduce ripple.
  • Resistors R1 (0603WAF3902T5E) and R2 (0603WAF2001T5E): These form a voltage divider connected to the feedback pin of the MT3608, setting the output voltage by regulating the feedback voltage to a set reference.
This specific design is used for low current applications with a maximum current requirement of 30mA, making it suitable for powering small electronic devices that need a stable higher voltage from a low voltage input source. If you have any further questions or need details on any specific part of the circuit, feel free to ask!
3mo
can you explain the circuit working and what could be the output voltage for 3.3...
@copilot can you explain the circuit working and what could be the output voltage for 3.3v of input for the circuit.
1y
This is a typical step-up (boost) converter using the MT3608 step-up adjustable DC-DC switcher IC. This type of converter is used to step up an input voltage to a higher level at the output.
Here is a basic rundown of the circuit function:

  1. The input voltage (2.5V to 24V) is fed into pin IN and EN of the MT3608. The IN pin is for the input supply, while the EN pin is a chip enable pin (active high). The input voltage is also bypassed by a 10uF capacitor (C2).
  2. The MT3608 switcher IC boosts the voltage at the SW pin, which is connected through the inductor L1, and the Schottky diode D1, to charge the output capacitor C1.
  3. The resistive divider network of R1 and R2 is connected to the feedback (FB) pin of MT3608. This network sets the output voltage using the following formula:
VOUT=VFB(1+R1R2) V_{OUT} = V_{FB} (1 + \frac{R1} {R2} )
where $ V_{FB} $ is typically 0.6V for MT3608.
Now, if you want to find the output voltage for an input of 3.3V, the input voltage doesn't directly relate to the output because this is a fixed output boost converter and the output voltage is determined by the feedback resistors R1 and R2. You can adjust these resistors to set the desired voltage.
If you are using the resistors as per your component list (39k for R2 and 2k for R1), the output voltage can be calculated as:
VOUT=0.6V(1+390002000) V_{OUT} = 0.6V * (1 + \frac{39000} {2000} )
VOUT=12.6V V_{OUT} = 12.6V
So, irrespective of the input being 3.3V, the output will be around 12.6V, provided the input voltage is within the operating range of the MT3608 (which is 2.5V to 24V) and the load does not require more current than the converter can supply.
1y
Hey, I'm copilot! I can help you with all kinds of stuff in your project. Reac...
Hey, I'm copilot! I can help you with all kinds of stuff in your project. Reach me at any time by tagging me on comments or in the chat with my handle, @copilot.
1y
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