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Properties
Properties describe core aspects of the project.
Pricing & Availability
Distributor | Qty 1 |
|---|---|
Arrow | $0.35–$0.77 |
Digi-Key | $0.85 |
LCSC | $0.14–$0.50 |
Mouser | $0.84 |
Verical | $0.52–$0.52 |
Assets
No assets added.
Controls
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Determine the Required Oscillator Frequency:
- A 20-minute period is 1200 seconds.
- The highest frequency division output is Q14, which divides the input frequency by $2^{14} = 16384$.
- Therefore, the oscillator frequency $f_{\text{osc}}$ should be:
fosc=1200s1×16384≈13.653Hz
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Set up the Oscillator:
- The CD4060BE uses an RC network to determine the oscillation frequency. The basic equation for the oscillator frequency is:
fosc=2.2×R×C1
- Solve for R and C to achieve the desired oscillator frequency.
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Connect the Circuit:
- Connect a resistor (R) and capacitor (C) to U1 as necessary for the oscillator.
- Connect U1:Q14 to your desired load or buffer to generate the square wave.
Example Calculation:- Assume $C = 100,nF = 100 \times 10^{-9} , \text{F}$
- Then $R = \frac{1}{2.2 \times 13.653 \times 100 \times 10^{-9}} \approx 331 , \text{k}\Omega$
Connections: