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calculate equivalent resistance

@copilot calculate equivalent resistance
1y
In your project, you have three resistors: R1, R2, and R3.
  • R1 and R2 are both connected in series with each other, in terms of their connections via Net 1 and Net 2.
  • This series combination of R1 and R2 is then connected in parallel with R3.
Let's calculate the equivalent resistance:
  1. Series Combination:
    The equivalent resistance of resistors in series is the sum of their resistances: Rseries=R1+R2=500Ω+500Ω=1000ΩR_{\text{series}} = R_1 + R_2 = 500\,\Omega + 500\,\Omega = 1000\,\Omega
  2. Parallel Combination:
    The equivalent resistance of resistors in parallel is given by: 1Req=1Rseries+1R3\frac{1}{R_{\text{eq}}} = \frac{1}{R_{\text{series}}} + \frac{1}{R_3}
    Substituting the values:
    1Req=11000Ω+1500Ω\frac{1}{R_{\text{eq}}} = \frac{1}{1000\,\Omega} + \frac{1}{500\,\Omega}
Now, let's calculate the equivalent resistance using this relationship.
Code Interpreter

Python


# Values of resistors in ohms
R1_R2_series = 1000  # R1 and R2 in series
R3 = 500  # R3

# Equivalent resistance calculation for parallel connection
R_eq = 1 / (1 / R1_R2_series + 1 / R3)
R_eq
The equivalent resistance of the entire network is approximately $333.33 , \Omega$.
1y
1
R1
Resistance
500 Ω
R3
Resistance
500 Ω
R2
Resistance
500 Ω

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