Tối ưu Mạch và Linh Kiện

Theo thông số hiện tại, các vị trí bố trí của các linh kiện phát nhiệt được xác định như sau:

Table


Linh kiệnVị trí PCB (mm)Ghi chú
U1 (BP2861CJ)23.73, 46.00Được đặt gần vùng trung tâm, giúp giảm chiều dài vòng chuyển mạch và tận dụng hiệu quả ground plane trên PCB nhôm.
L2 (CD75T125NP-471KC)22.34, 35.77Gần với U1 (cách khoảng 10 mm), thuận lợi cho việc giảm điện cảm của mạch chuyển mạch và cải thiện EMI.
BD1 (ABS10)39.71, 27.86Cách U1 khoảng 24 mm, điều này tạo ra một vòng mạch dài hơn một chút. Nếu các trace kết nối được thiết kế ngắn gọn và với ground plane liên tục, việc này có thể chấp nhận được; tuy nhiên, để giảm nhiễu EMI và giảm tổn thất do đường dây (parasitic inductance), bạn có thể cân nhắc điều chỉnh vị trí BD1 gần hơn với U1 và L2 nếu điều kiện layout cho phép.
Tóm lại:
  • U1 và L2: Được bố trí gần nhau, tối ưu cho vòng mạch chuyển mạch và giảm EMI, đồng thời phối hợp với PCB nhôm sẽ hỗ trợ tản nhiệt tốt.
  • BD1: Mặc dù vị trí hiện tại có thể chấp nhận nếu đường mạch được routing cẩn thận, nhưng để đạt hiệu suất EMI tối ưu, việc rút ngắn khoảng cách đường dẫn (đưa BD1 gần hơn với U1) có thể đem lại lợi ích bổ sung.
Bạn có muốn áp dụng các chỉnh sửa về vị trí của BD1 để giảm khoảng cách với U1 (và L2) hay cần thêm gợi ý về cách routing cụ thể cho vòng mạch chuyển mạch không?
Relocate BD1
Routing Suggestions
Thermal Management
what shoud I connect to D1 (ABS10), Is that correct ?

@copilot what shoud I connect to D1 (ABS10), Is that correct ?
1y
Let's look at the connections for D1, which is a bridge rectifier:
  • Pin + is connected to R1:P1 and L1:1 via Net 3.
  • Pin P3 is connected to U2:2 via Net 1.
  • Pin P4 is connected to Net 2.
  • Pin - doesn't have a specific net assignment in your project's description.
Given that D1 is a bridge rectifier:
  • The AC inputs are usually connected to pins P3 and P4.
  • The DC output is typically across pins + (positive) and - (negative).
To complete the rectifier circuit, you should ensure that:
  • Connect the AC power source to D1:P3 and D1:P4.
  • Connect load/next circuit stage from D1:+ and D1:-.
Please verify your setup with this overview, and feel free to correct any assumptions or provide additional details.
1y
2
How can I desgin the Buck converter schematic with IC BP2861CJ and required para...

@copilot How can I desgin the Buck converter schematic with IC BP2861CJ and required parameters:
  • Buck Converter
  • Use IC BP2861CJ
  • Input voltage: 220VAC
  • Input Power: 9W
  • Power Factor: 0.5
  • Rectifier diode output current: 30mA
  • LED Output Voltage: 81VDC
  • LED Output Current: 105mA
  • Driver Efficiency : 90%
1y
Designing a buck converter schematic using the BP2861CJ involves several steps. Here’s an outline of the process, along with the necessary components and their connection:
Key Components Buck Converter Design Steps
  1. AC Input and Rectification:
  2. Rectifier Output Smoothing:
    • Connect the DC output of BD1 to a smoothing capacitor like C1.
  3. Buck Converter Stage:
    • Connect BD1:+ to U1:HV.
    • Connect U1:DRAIN to L1:1.
    • Connect L1:2 to LED string's anodes.
    • Place a capacitor (e.g., C3) parallel to the output for smoothing.
    • Connect feedback and compensation resistors to U1:CS.
  4. LED Output Stage:
    • Ensure the LED array supports the output voltage of 81V81 \, V and current of 105mA105 \, mA.
    • Connect LEDs in series to achieve the required voltage and current.
  5. Feedback and Current Sensing:
    • Calculate and connect appropriate resistor values for feedback and current sensing, ensuring the output voltage and current are within required parameters.
    • Use resistors like R1, R2, and feedback connections to U1:CS.
Considerations
  • Ensure all components are rated for the voltages and currents involved, especially the input stage and smoothing capacitors.
  • The power factor correction might require more components if required.
  • Validate design calculations such as inductor and capacitor values using design formulas for buck converters.
If you'd like, we can go into more detail on any of these steps or check calculations for specific components!
1y
7
Please Calculate the parameters of C1 for me with parameter requirements: Buck C...

@copilot Please Calculate the parameters of C1 for me with parameter requirements: Buck Converter Input Voltage: 220VAC Input Power: 9W, Power Factor: 0.5; Output Current after diode bridge rectifier : 30mA ; Frequency after diode bridge rectifier : 100Hz
1y
To calculate the parameters for C1, we need to determine its capacitance needed to smooth the rectified voltage from the AC source, considering input voltage, power, and desired output characteristics.
Key Parameters and Assumptions:
  • Input Voltage (V_in_rms): 220 V AC
  • Input Power (P_in): 9 W
  • Power Factor (PF): 0.5
  • Output Current (I_out): 30 mA
  • Frequency: 100 Hz
Steps:
  1. Calculate DC Input Voltage after Rectification (V_in_dc):
    The AC RMS voltage is converted to a DC peak voltage using the formula:
    Vin_peak=Vin_rms×2V_{\text{in\_peak}} = V_{\text{in\_rms}} \times \sqrt{2}
    The average rectified voltage can be approximated as:
    Vin_dc=2Vin_peakπV_{\text{in\_dc}} = \frac{2 \cdot V_{\text{in\_peak}}}{\pi}
  2. Calculate the Load Resistance (R_load):
    Using the power factor and input power:
    Rload=(Vin_rms2Pin×PF)R_{\text{load}} = \left(\frac{V_{\text{in\_rms}}^2}{P_{\text{in}} \times PF}\right)
  3. Calculate Capacitance (C):
    The ripple voltage ($V_{\text{ripple}}$) is estimated using:
    Vripple=Iout×1f×CV_{\text{ripple}} = I_{\text{out}} \times \frac{1}{f \times C}
    Solving for $C$, we have:
    C=IoutVripple×fC = \frac{I_{\text{out}}}{V_{\text{ripple}} \times f}
Assuming a reasonable ripple voltage, typically a small percentage of V_in_dc (e.g., 5%). Let's calculate with these values.
Code Interpreter

Python


import numpy as np

# Given values
V_in_rms = 220  # RMS input voltage in V
P_in = 9       # Input power in W
PF = 0.5       # Power factor
I_out = 30e-3  # Output current in A
f = 100        # Frequency in Hz

# Step 1: Calculate the DC input voltage after rectification
V_in_peak = V_in_rms * np.sqrt(2)
V_in_dc = (2 * V_in_peak) / np.pi

# Step 2: Calculate the load resistance
R_load = (V_in_rms**2) / (P_in * PF)

# Assume ripple voltage as 5% of V_in_dc for calculation
V_ripple = 0.05 * V_in_dc

# Step 3: Calculate the capacitance
C = I_out / (V_ripple * f)

V_in_dc, R_load, V_ripple, C
Here are the calculated parameters for C1:
  • DC Input Voltage (after rectification): ( 198.07 , \text{V} )
  • Load Resistance (R_load): ( 10755.56 , \Omega )
  • Assumed Ripple Voltage (5% of DC voltage): ( 9.90 , \text{V} )
  • Capacitance (C1): ( 30.29 , \mu\text{F} )
These values imply that C1 should have a capacitance of approximately ( 30.29 , \mu\text{F} ) to achieve the specified ripple voltage under the given conditions. Let me know if there's anything you'd like to adjust or further explore!
1y
8
L1
Inductance
1mH
R3
Resistance
Resistance
Resistance
8.2 Ω
Power
0.125 W
R2
Resistance
Resistance
Resistance
2.2 Ω
Power
0.125 W
U1
C1
Capacitance
4.7uF


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AT06.V3 9W DOB V3.1

AT06.V3 9W DOB V3.1 thumbnail
  • Buck Converter
  • Use IC BP2861CJ
  • Required Parameters: Input voltage: 220VAC Input Power: 9W Power Factor: 0.5 LED Output Voltage: 81VDC LED Output Current: 105mA Driver Efficiency : 90%

Properties

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