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Réaliser un circuit détecteur de minimum de 2 nombres de 4 bits signés reçus en ...
natevector

natevector

@copilot Réaliser un circuit détecteur de minimum de 2 nombres de 4 bits signés reçus en entrée, utiliser les circuits intégrés appropriés.
2y

copilot

Le fonctionnement d'un circuit détecteur de minimum est que si une entrée est plus petite que l'autre entrée, alors une sortie spécifique devrait être active. Pour réaliser ce circuit pour des nombres de 4 bits signés, nous avons besoin de quelques composants supplémentaires en plus de U1 (SN74LS283D, qui est un additionneur 4 bits).
Les composants nécessaires sont:
  1. Additionneur 4 bits (SN74LS283D, déjà dans le projet)
  2. Comparateur 4 bits (ex : SN74LS85)
Voici comment vous pouvez connecter ces composants:
  1. Connectez les pins A1, A2, A3, A4 de U1 à l'entrée des 4 bits du premier nombre.
  2. Connectez les pins B1, B2, B3, B4 de U1 à l'entrée des 4 bits du deuxième nombre.
Pour le comparateur 4 bits (pour lequel nous utiliserons U2 comme désignateur):
  1. Connectez les pins A0, A1, A2, A3 (les entrées A du comparateur) à la sortie de l'additionneur 4 bits (les pins 1, 4, 13, 10 de U1 respectivement).
  2. Connectez GND à la masse et VCC à l'alimentation.
  3. Les pins B0, B1, B2, B3 (les entrées B du comparateur) seront connectées à 0 (puisque nous comparons le résultat de l'addition avec zéro).
La sortie de la comparaison sera sur les pins de sortie du comparateur (les pins 7, 6, 5). Vous pouvez choisir l'une de ces broches selon si vous voulez un signal actif haut ou actif bas lorsque le premier nombre est inférieur au deuxième.
Veuillez noter que pour les nombres signés, le bit de poids le plus élevé (MSB) est le bit de signe, donc assurez-vous de l'interpréter correctement lors de l'établissement de vos entrées et de l'interprétation de la sortie.
2y
natevector

natevector

can you propose a differente methode
2y

copilot

Certainly, you can implement a minimum detector of two signed 4-bit numbers using Two's complement arithmetic method without using the addition operation. You would need:
  • Two 4-bit inverters (7404 hex inverters)
  • One 4-bit binary adder (SN74LS283D that we already have in the project)
  • One 1-bit binary adder (74LS83)
  • One 4-bit AND gate (74HC08).
Here's how you could set this up:
  1. Negative Number Detector:
    • Wire the most significant bit (MSB - bits 4) of both 4-bit inputs to separate inputs of the AND gate (designate this as U3, let's say Pin 1 and Pin 2)
    • The output of AND gate (U3, Pin 3) is High when both numbers are negative numbers
  2. Two's Complement:
    • When the Negative Number Detector output is High, generate 2's complement for both 4-bit numbers
    • Connect the input bits to the 4-bit inverter, add an additional 1-bit binary adder for the '1' in Two's complement process
  3. Comparison:
    • For both 4-bit binary numbers, use bit-wise AND operation with Negative Number Detector output at each bit position using 7404's NOT and 74LS08's AND gates
    • This makes the comparison operation works for positive numbers when both inputs are positive and for negative numbers when both inputs are negative (due to Two's complement operation)
    • Output High when first number is less than the second for all 4-bit positions
Note again that for signed 4-bit numbers, the most significant bit (MSB or Bit 4) represents the sign of the number (1 for negative, 0 for positive), so the circuit has to correctly interpret and handle this bit.
2y
3
How to design a decimal adder for two numbers represented in the excess-3 code. ...
natevector

natevector

explaine more the correction step
2y
natevector

natevector

@copilot How to design a decimal adder for two numbers represented in the excess-3 code. Find the correction after adding the two numbers with a 4-bit binary adder and construct the decimal adder with two 4-bit adders and an inverter
2y

copilot

Designing a decimal adder for two numbers represented in the excess-3 code involves two main stages:
  1. Converting the excess-3 numbers to binary, which can be realized with a 4-input, 4-output invertor.
  2. Binary addition of the converted numbers, which can be realized with two 4-bit binary adders.
Step-by-step process:
  1. Conversion to Binary
    Each excess-3 number has to be inverted to obtain its binary representation. This involves inverting each bit. In Flux, you can add four NOT gates (inverters) for each excess-3 number.
    Let's represent your inverters as U1:{NOT1, NOT2, NOT3, NOT4} and U2:{NOT1, NOT2, NOT3, NOT4}.
  2. Binary Addition
    Once you have converted the input numbers to binary, you can proceed to add them using 4-bit binary adders.
    You can represent your adders using the designators U3: {ADD1} and U4: {ADD2}.
    Connect the outputs of each digit from the NOT gates to each corresponding adder inputs:
    • Connect U1:NOT1 output to U3:ADD1:A1 input, and U2:NOT1 output to U3:ADD1:B1 input.
    • Connect U1:NOT2 output to U3:ADD1:A2 input, and U2:NOT2 output to U3:ADD1:B2 input.
    • Connect U1:NOT3 output to U3:ADD1:A3 input, and U2:NOT3 output to U3:ADD1:B3 input.
    • Connect U1:NOT4 output to U3:ADD1:A4 input, and U2:NOT4 output to U3:ADD1:B4 input.
  3. Correction
    After the addition process, the output may be a binary number greater than 9 (1001 in binary). In decimal system, we carry the excess to the next decimal position. Similarly, in the excess-3 system, a carry out is generated when the sum is greater than or equal to 1100 (which is 12 in decimal, corresponding to 9 in excess-3).
    In this case, add 0011 (which represents 3 in binary) to the sum using the second 4-bit adder U4: {ADD2}.
    Connect the outputs from U3: {ADD1} to the inputs of U4: {ADD2}, and connect a constant logic-high (VCC) to the remaining inputs of U4: {ADD2} to represent the binary digit 3 (0011).
Note: Actual pin names may vary based on the specific ICs used for NOT gates and adders.
Remember to connect power and ground to the ICs, and to provide inputs to the circuit.
I hope this helps. Let me know if you have any further questions.
2y
1
please explain what U2 does.
natevector

natevector

@copilot please explain what U2 does.
2y

copilot

U2 is an SN7432N chip, a quad 2-input OR gate from Texas Instruments.
This integrated circuit consists of four independent gate circuits in a single package, each circuit functioning as a 2-input OR gate.
  • An OR gate is a digital logic gate that outputs true or high only when at least one of its inputs is true or high.
  • The inputs are often referred to as 'A' and 'B', and the output as 'Y'.
  • The pin layout for each of the four OR gates in the SN7432N chip is as follows:
    • Gate 1: Inputs at pins 1 (1A) and 2 (1B), output at pin 3 (1Y)
    • Gate 2: Inputs at pins 4 (2A) and 5 (2B), output at pin 6 (2Y)
    • Gate 3: Inputs at pins 9 (3A) and 10 (3B), output at pin 8 (3Y)
    • Gate 4: Inputs at pins 12 (4A) and 13 (4B), output at pin 11 (4Y)
  • The remaining pins are for power supply (VCC - Pin 14) and ground (GND - Pin 7).
Note that the OR gate operation follows this truth table:

Table

ABOutput Y
000
011
101
111
2y
4
U2
U1

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