Boost Converter Output Inquiry

Here are three 1 A–capable boost converters matching your 1.8–6 V→10 V, ≥1 A output requirement:

Table


PartMPNDatasheetPackage
MT3608MT3608DatasheetSOT-23-6
LM2577SX-ADJ/NOPBLM2577SX-ADJ/NOPBDatasheetTO-263-3
TPS61088RHLRTPS61088RHLRDatasheetWQFN-EP-24
Recommendations:
  • MT3608
    • Pros: Very low VIN operation (down to ~2 V), small SOT-23-6 package, common on hobby modules.
    • Cons: Efficiency and output current taper off near VIN = 1.8 V; may struggle to sustain a full 1 A at lower VIN.
  • LM2577SX-ADJ/NOPB
    • Pros: Robust 3 A capability, adjustable output, good for VIN ≥ 3 V.
    • Cons: Higher minimum VIN (~3 V), larger TO-263-3 package.
  • TPS61088RHLR
    • Pros: High efficiency (>95 %), true full-load 1 A or more across VIN 1.8–6 V, integrated synchronous MOSFETs.
    • Cons: QFN-24 package (requires fine-pitch assembly), higher cost.
Let me know which one fits your board constraints and sourcing preferences!
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use R1 = 1.8MOhms and R2 = 205kOhms for 12V Output as per datasheet application ...

use R1 = 1.8MOhms and R2 = 205kOhms for 12V Output as per datasheet application circuit
2y
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R1 is 1.8MOhms and i want an output voltage of 10V. What do I pick for R2? Here'...

@copilot R1 is 1.8MOhms and i want an output voltage of 10V. What do I pick for R2? Here's the equation from the datasheet
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2y
To calculate the value for R2 that will set the output voltage (VOUTV_{OUT}) of the boost converter to 10V, we can rearrange the formula provided:
VOUT=1.233V×(1+R1R2)V_{OUT} = 1.233V \times \left( 1 + \frac{R1}{R2} \right)
Rearranging the formula to solve for R2:
R1R2=VOUT1.233V1\frac{R1}{R2} = \frac{V_{OUT}}{1.233V} - 1
Given that R1 is 1.8MΩ (1,800,000Ω) and the desired output voltage is 10V:
R1R2=10V1.233V1=8.1041=7.104\frac{R1}{R2} = \frac{10V}{1.233V} - 1 = 8.104 - 1 = 7.104
Now we solve for R2:
R2=R17.104=1,800,000Ω7.104253,363ΩR2 = \frac{R1}{7.104} = \frac{1,800,000Ω}{7.104} ≈ 253,363Ω
Since standard resistor values might not exactly match this calculated value, you would typically select the nearest standard value. A common approach is to use a standard E-series value, such as E24 or E96 series, which provides a range of values at specified tolerance levels. The nearest E24 value to 253kΩ is 249kΩ or 255kΩ. You might select 249kΩ to provide a slightly higher output voltage than 10V, to account for possible tolerances, or if precision is critical, you could put two resistors in series or parallel to achieve the desired value as close as possible.
To summarize:
  • R2 calculated value: ≈ 253,363Ω
  • Possible standard E24 value: 249kΩ or 255kΩ
Please note that resistor tolerances may affect your output voltage, so if this is a precise application, make sure to use high-precision resistors or adjust the value of R2 as necessary after testing.
2y
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IC1
R2
Resistance
249kΩ
D1
C2
Capacitance
4.7uF
R1
Resistance
1.8MΩ
L1
Height
1 mm
Inductance
6.8uH
VOUT
VIN
GNDTERMINAL
CFF
Capacitance
4.7pF
C1
Capacitance
10uF
EN

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    TPS61040DBVR Boost Converter Module

    TPS61040DBVR Boost Converter Module thumbnail
    Boost Converter 1.8V-6V input. 10.15V Output. 350mA max current.
    Enable is not internally pulled high or low. Please pull up or down according to your application.

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