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How make a voltage multiplier with 2 opamps

@copilot How make a voltage multiplier with 2 opamps
1y
To create a voltage multiplier (specifically a voltage doubler) using two op-amps, you can use a configuration known as the "capacitor-based voltage doubler." Below is a guide to implementing this using the components you have:
Components Required
  • Two op-amps (LM741)
  • Capacitors (C1, C2)
  • Resistors (R1, R2, R3, R4)
  • Diodes (D1, D2, D3, D4 like 1N4007W)
  • Power Source (BATT1)
Schematic and Connections
The basic idea is to charge capacitors in parallel and discharge them in series to create a higher voltage. Here is the step-by-step connection:
  1. First Op-Amp Stage for Voltage Inversion:
    • Components: U1 (op-amp), R1 (resistor, 10k), R2 (resistor, 10k), C1 (capacitor)
    • Connect R1:1 to U1:2 (-)
    • Connect R1:2 to Net 3
    • Connect U1:3 (+) to Net 3
    • Connect R2:1 to BATT1:+ and R2:2 to U1:6 (OUTPUT)
    • Connect C1: $V-$ to U1:4 (V-)
    • Connect BATT1: (-) to net 7
    • Connect D2: $K$ to U1:6 and D2:$A$ to VR1:CW
    • Connect C1: Right side to Net 6 (for output)
  2. Second Op-Amp Stage for Summing the Voltages:
    • Components: U2 (op-amp), R3 (resistor), R4 (resistor), C2 (capacitor)
    • Connect R3:1 to U2:2 (-)
    • Connect R3:2 to Net 4
    • Connect U2:3 (+) to Net 4
    • Connect R4:1 to BATT1:+ and R4:2 to U2:6 (OUTPUT)
    • Connect C2: $V-$ to D3: facing inwards
    • Connect BATT1: (-) to net 7
    • Connect [ VR1]:CW middle point to Net 4
Voltage Calculation
  1. Inverting stage output: Vout(U1)=VinV_{out(U1)} = -V_{in}
  2. Summing Stage output: Vout(U2)=Vin+(Vin)=2VinV_{out(U2)} = V_{in} + (-V_{in}) = 2V_{in}
Let me know if you need further assistance or corrections with specific component placements!
1y
2
R4
Resistance
4.7kΩ
R3
Resistance
470 Ω
R1
Resistance
1kΩ
BATT1
R2
Resistance
10kΩ
U2
U1

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