Embedded System Design Inquiry

flux

The required series resistance is:
R=4 V−2.1 V2 mA=950  ΩR = \frac{4\text{ V} - 2.1\text{ V}}{2\text{ mA}} = 950\;\Omega
A standard 1 kΩ (0603) resistor is the closest E-series value.
Shall I add a 1 kΩ 0603 resistor to your schematic for the LED?
bayboy

bayboy

@library add a 1 kΩ 0603 resistor to the LED’s series branch.

flux

I can add the following component to your schematic:
bayboy

bayboy

@library add CRG0603F1K0 as the LED series resistor R16

flux

I can add the following component:
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R16

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