Power net portal is a special schematic object used to define a power or ground net. Power ports allow you to conveniently indicate a power net at any location in the design. Power nets of the same designator automatically connect throughout your design #portal #power

A generic fixed inductor for rapid developing circuit topology. *You can now change the footprint and 3D model at the top level anytime you want. This is the power of #generics

Simulating the circuit requires knowing the functionality and intended behavior, especially since this project appears to be an astable multivibrator. Astable multivibrators are circuits that oscillate between two states without needing an external trigger. They commonly use two transistors, a few resistors, and capacitors.

Key Components and Connections

Two transistors (e.g., Q1 and Q2)

Four resistors (e.g., R1 to R4)

Two capacitors (e.g., one of them is the 100p capacitor)

Power supply PS1

To proceed with the simulation, I will assume this configuration corresponds to a typical astable multivibrator setup. Let's outline the simulation process:

Assumptions for Simulation

Transistor type: Assume NPN due to common use in astable circuits.

Capacitor values: Use 100pF for each capacitor.

Power supply: Use the 9V provided by PS1.

Resistors: Assume R1 to R4 have correct values for oscillation.

Circuit Behavior

The circuit will toggle between two states, turning each transistor on and off alternately.

The frequency of oscillation is determined by the resistor-capacitor (RC) network.

Simulation Steps

Define the schematic: Identify the connections between components.

Set initial conditions: Assume initial states for the transistors.

Run a time-based analysis to observe voltage and current changes.

Would you like to proceed with simulating this in a more interactive way, such as using Python for calculations, or is there a specific tool you prefer for simulation?

The voltage on the base of the transistors in an astable multivibrator depends on several factors, including the transistors' base-emitter voltage (V_BE), the resistances and capacitances in the circuit. However, direct information about these parameters is not provided in your project description.

In Astable Multivibrator configurations using bipolar junction transistors (like your circuit with designators Q1 and Q2), the average voltage at the base of the transistor cannot be directly calculated without knowing the values of the resistors and capacitors as well as the supply voltage (V_CC).

The base voltage is usually ~0.7V higher than the emitter voltage due to the base-emitter junction of a BJT transistor being forward-biased. Therefore, we can say in terms of the emitter voltage that V_B = V_E + 0.7V (approx).

For astable oscillators, the time high (T1) and time low (T2) periods depend on the Resistors R1, R2, R3, R4 and capacitors values (which vary in your project), leading to the calculation of the frequency of operation. These all affect the average values you seek.

Given this information, it unfortunate to let you know that without additional details on the resistors, capacitors and supply voltage, it isn't possible to provide an accurate response for the average voltage on the base of the transistors. If you can send this information, we can help you find a more precise answer.

To calculate the time base or frequency of the LED turning on and off in an astable multivibrator circuit, it's necessary to understand the values of capacitors and resistors involved.

The frequency of oscillation in an astable multivibrator circuit using resistors and capacitors (R1, R2 and C1, C2) is given by the formula:

[f = \frac{1}{ln(2) (R1+2R2)*C}]

In this circuit, it seems like there might be some information missing, like which capacitors and resistors are used in the timing network and how the LEDs are connected. Could you clarify that so we can proceed with the calculation?

1y

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Passive Components

Resistor Power Rating

Beta

Checks that the power traveling across a given resistor is under its rating with 50% headroom.